Base | Representation |
---|---|
bin | 1011000010001011100110… |
… | …1000110100110101000011 |
3 | 1120221211002001112200001101 |
4 | 2300202321220310311003 |
5 | 3042233021121143021 |
6 | 41445224421115231 |
7 | 2361341541420502 |
oct | 260427150646503 |
9 | 46854061480041 |
10 | 12132102131011 |
11 | 3958217408095 |
12 | 143b348558b17 |
13 | 6a008ac4a205 |
14 | 2dd2a832a839 |
15 | 1608b55bca91 |
hex | b08b9a34d43 |
12132102131011 has 2 divisors, whose sum is σ = 12132102131012. Its totient is φ = 12132102131010.
The previous prime is 12132102130987. The next prime is 12132102131081. The reversal of 12132102131011 is 11013120123121.
It is a weak prime.
It is an emirp because it is prime and its reverse (11013120123121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12132102131011 - 215 = 12132102098243 is a prime.
It is a super-3 number, since 3×121321021310113 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12132102131011.
It is not a weakly prime, because it can be changed into another prime (12132102131081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066051065505 + 6066051065506.
It is an arithmetic number, because the mean of its divisors is an integer number (6066051065506).
Almost surely, 212132102131011 is an apocalyptic number.
12132102131011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12132102131011 is an equidigital number, since it uses as much as digits as its factorization.
12132102131011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 12132102131011 its reverse (11013120123121), we get a palindrome (23145222254132).
The spelling of 12132102131011 in words is "twelve trillion, one hundred thirty-two billion, one hundred two million, one hundred thirty-one thousand, eleven".
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