Base | Representation |
---|---|
bin | 100100001010000… |
… | …0010110101010001 |
3 | 10010112212122210002 |
4 | 1020110002311101 |
5 | 4441040322113 |
6 | 320215215345 |
7 | 42031102103 |
oct | 11024026521 |
9 | 3115778702 |
10 | 1213214033 |
11 | 572911729 |
12 | 29a377555 |
13 | 16446cc35 |
14 | b71ad573 |
15 | 7179ac58 |
hex | 48502d51 |
1213214033 has 2 divisors, whose sum is σ = 1213214034. Its totient is φ = 1213214032.
The previous prime is 1213214021. The next prime is 1213214069. The reversal of 1213214033 is 3304123121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 823862209 + 389351824 = 28703^2 + 19732^2 .
It is a cyclic number.
It is not a de Polignac number, because 1213214033 - 210 = 1213213009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1213213996 and 1213214014.
It is not a weakly prime, because it can be changed into another prime (1213214633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606607016 + 606607017.
It is an arithmetic number, because the mean of its divisors is an integer number (606607017).
Almost surely, 21213214033 is an apocalyptic number.
It is an amenable number.
1213214033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213214033 is an equidigital number, since it uses as much as digits as its factorization.
1213214033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
The square root of 1213214033 is about 34831.2221002939. Note that the first 3 decimals coincide. The cubic root of 1213214033 is about 1066.5448959408.
Adding to 1213214033 its reverse (3304123121), we get a palindrome (4517337154).
The spelling of 1213214033 in words is "one billion, two hundred thirteen million, two hundred fourteen thousand, thirty-three".
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