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121321421341 = 636719054723
BaseRepresentation
bin111000011111101010…
…0011111101000011101
3102121011002122202210121
41300333110133220131
53441431240440331
6131422335034541
711523313031521
oct1607724375035
9377132582717
10121321421341
11474a786357a
121b61a36ba51
13b595bb26a3
145c2ca41d81
153250ec7c11
hex1c3f51fa1d

121321421341 has 4 divisors (see below), whose sum is σ = 121340482432. Its totient is φ = 121302360252.

The previous prime is 121321421327. The next prime is 121321421369. The reversal of 121321421341 is 143124123121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121321421341 - 217 = 121321290269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121321421311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9520995 + ... + 9533728.

It is an arithmetic number, because the mean of its divisors is an integer number (30335120608).

Almost surely, 2121321421341 is an apocalyptic number.

It is an amenable number.

121321421341 is a deficient number, since it is larger than the sum of its proper divisors (19061091).

121321421341 is an equidigital number, since it uses as much as digits as its factorization.

121321421341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19061090.

The product of its digits is 1152, while the sum is 25.

Adding to 121321421341 its reverse (143124123121), we get a palindrome (264445544462).

The spelling of 121321421341 in words is "one hundred twenty-one billion, three hundred twenty-one million, four hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 6367 19054723 121321421341