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12132201020131 is a prime number
BaseRepresentation
bin1011000010001011111110…
…0010000011101011100011
31120221211022221121202102101
42300202333202003223203
53042233221430121011
641445242312431231
72361344152105123
oct260427742035343
946854287552371
1012132201020131
11395826820aa35
12143b3756a8517
136a00a559219a
142dd2b750cc83
151608be1032c1
hexb08bf883ae3

12132201020131 has 2 divisors, whose sum is σ = 12132201020132. Its totient is φ = 12132201020130.

The previous prime is 12132201020057. The next prime is 12132201020221. The reversal of 12132201020131 is 13102010223121.

12132201020131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12132201020131 - 237 = 11994762066659 is a prime.

It is a super-2 number, since 2×121322010201312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12132201020099 and 12132201020108.

It is not a weakly prime, because it can be changed into another prime (12132201050131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066100510065 + 6066100510066.

It is an arithmetic number, because the mean of its divisors is an integer number (6066100510066).

Almost surely, 212132201020131 is an apocalyptic number.

12132201020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12132201020131 is an equidigital number, since it uses as much as digits as its factorization.

12132201020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12132201020131 its reverse (13102010223121), we get a palindrome (25234211243252).

The spelling of 12132201020131 in words is "twelve trillion, one hundred thirty-two billion, two hundred one million, twenty thousand, one hundred thirty-one".