Base | Representation |
---|---|
bin | 10001101001111010001… |
… | …110010001101100001101 |
3 | 11021222120011210211200020 |
4 | 101221322032101230031 |
5 | 124334144210342201 |
6 | 2325203434052353 |
7 | 153440001145131 |
oct | 21517216215415 |
9 | 4258504724606 |
10 | 1213231340301 |
11 | 42858a50a982 |
12 | 17717087a0b9 |
13 | 8a53a897a56 |
14 | 42a138b33c1 |
15 | 2185b5d7a36 |
hex | 11a7a391b0d |
1213231340301 has 4 divisors (see below), whose sum is σ = 1617641787072. Its totient is φ = 808820893532.
The previous prime is 1213231340297. The next prime is 1213231340303. The reversal of 1213231340301 is 1030431323121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1213231340301 - 22 = 1213231340297 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213231340303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202205223381 + ... + 202205223386.
It is an arithmetic number, because the mean of its divisors is an integer number (404410446768).
Almost surely, 21213231340301 is an apocalyptic number.
It is an amenable number.
1213231340301 is a deficient number, since it is larger than the sum of its proper divisors (404410446771).
1213231340301 is an equidigital number, since it uses as much as digits as its factorization.
1213231340301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 404410446770.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1213231340301 its reverse (1030431323121), we get a palindrome (2243662663422).
The spelling of 1213231340301 in words is "one trillion, two hundred thirteen billion, two hundred thirty-one million, three hundred forty thousand, three hundred one".
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