Base | Representation |
---|---|
bin | 1011000010001100110010… |
… | …1110101000011101111111 |
3 | 1120221211220101020001102112 |
4 | 2300203030232220131333 |
5 | 3042234200114422401 |
6 | 41445320302044235 |
7 | 2361352511012612 |
oct | 260431456503577 |
9 | 46854811201375 |
10 | 12132422420351 |
11 | 395837118a222 |
12 | 143b41787967b |
13 | 6a010c40002c |
14 | 2dd2d8aa2179 |
15 | 1608d37883bb |
hex | b08ccba877f |
12132422420351 has 4 divisors (see below), whose sum is σ = 12149534441400. Its totient is φ = 12115310399304.
The previous prime is 12132422420323. The next prime is 12132422420381. The reversal of 12132422420351 is 15302422423121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12132422420351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12132422420381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8556009461 + ... + 8556010878.
It is an arithmetic number, because the mean of its divisors is an integer number (3037383610350).
Almost surely, 212132422420351 is an apocalyptic number.
12132422420351 is a deficient number, since it is larger than the sum of its proper divisors (17112021049).
12132422420351 is an equidigital number, since it uses as much as digits as its factorization.
12132422420351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17112021048.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 12132422420351 its reverse (15302422423121), we get a palindrome (27434844843472).
The spelling of 12132422420351 in words is "twelve trillion, one hundred thirty-two billion, four hundred twenty-two million, four hundred twenty thousand, three hundred fifty-one".
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