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12132445333 = 55721781769
BaseRepresentation
bin10110100110010011…
…00110110010010101
31011022112100002012011
423103021212302111
5144321401222313
65323520224221
7606440040511
oct132311466225
934275302164
1012132445333
1151664a3828
12242716b071
1311b4728348
14831457141
154b01d393d
hex2d3266c95

12132445333 has 4 divisors (see below), whose sum is σ = 12154227660. Its totient is φ = 12110663008.

The previous prime is 12132445319. The next prime is 12132445357. The reversal of 12132445333 is 33354423121.

It is a happy number.

12132445333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33354423121 = 57158414051.

It can be written as a sum of positive squares in 2 ways, for example, as 6024553924 + 6107891409 = 77618^2 + 78153^2 .

It is a cyclic number.

It is not a de Polignac number, because 12132445333 - 217 = 12132314261 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12132445295 and 12132445304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12132445363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10890328 + ... + 10891441.

It is an arithmetic number, because the mean of its divisors is an integer number (3038556915).

Almost surely, 212132445333 is an apocalyptic number.

It is an amenable number.

12132445333 is a deficient number, since it is larger than the sum of its proper divisors (21782327).

12132445333 is an equidigital number, since it uses as much as digits as its factorization.

12132445333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21782326.

The product of its digits is 25920, while the sum is 31.

Adding to 12132445333 its reverse (33354423121), we get a palindrome (45486868454).

It can be divided in two parts, 121 and 32445333, that multiplied together give a palindrome (3925885293).

The spelling of 12132445333 in words is "twelve billion, one hundred thirty-two million, four hundred forty-five thousand, three hundred thirty-three".

Divisors: 1 557 21781769 12132445333