Base | Representation |
---|---|
bin | 10001101001111110011… |
… | …000110110001101101011 |
3 | 11021222202001022002212202 |
4 | 101221332120312031223 |
5 | 124334320103021303 |
6 | 2325214411530415 |
7 | 153441510131462 |
oct | 21517630661553 |
9 | 4258661262782 |
10 | 1213301220203 |
11 | 4286159a9766 |
12 | 177190159a0b |
13 | 8a54c1c39c7 |
14 | 42a1cca39d9 |
15 | 218627dcc88 |
hex | 11a7e63636b |
1213301220203 has 2 divisors, whose sum is σ = 1213301220204. Its totient is φ = 1213301220202.
The previous prime is 1213301220193. The next prime is 1213301220311. The reversal of 1213301220203 is 3020221033121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1213301220203 - 224 = 1213284442987 is a prime.
It is a super-2 number, since 2×12133012202032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1213301220403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606650610101 + 606650610102.
It is an arithmetic number, because the mean of its divisors is an integer number (606650610102).
Almost surely, 21213301220203 is an apocalyptic number.
1213301220203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213301220203 is an equidigital number, since it uses as much as digits as its factorization.
1213301220203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1213301220203 its reverse (3020221033121), we get a palindrome (4233522253324).
The spelling of 1213301220203 in words is "one trillion, two hundred thirteen billion, three hundred one million, two hundred twenty thousand, two hundred three".
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