Base | Representation |
---|---|
bin | 1011000010001111000001… |
… | …1010100000001010010111 |
3 | 1120221220110002210022100222 |
4 | 2300203300122200022113 |
5 | 3042241411401420343 |
6 | 41445455530224555 |
7 | 2361403400630210 |
oct | 260436032401227 |
9 | 46856402708328 |
10 | 12133021123223 |
11 | 3958649131590 |
12 | 143b56428515b |
13 | 6a01a64633a0 |
14 | 2dd3543cc407 |
15 | 16091b0eba68 |
hex | b08f06a0297 |
12133021123223 has 64 divisors (see below), whose sum is σ = 17221486464000. Its totient is φ = 8232243010560.
The previous prime is 12133021123219. The next prime is 12133021123243. The reversal of 12133021123223 is 32232112033121.
It is a cyclic number.
It is not a de Polignac number, because 12133021123223 - 22 = 12133021123219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12133021123192 and 12133021123201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12133021123243) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3062453 + ... + 5800401.
It is an arithmetic number, because the mean of its divisors is an integer number (269085726000).
Almost surely, 212133021123223 is an apocalyptic number.
12133021123223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12133021123223 is a deficient number, since it is larger than the sum of its proper divisors (5088465340777).
12133021123223 is a wasteful number, since it uses less digits than its factorization.
12133021123223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2738232.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 12133021123223 its reverse (32232112033121), we get a palindrome (44365133156344).
The spelling of 12133021123223 in words is "twelve trillion, one hundred thirty-three billion, twenty-one million, one hundred twenty-three thousand, two hundred twenty-three".
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