Base | Representation |
---|---|
bin | 1011000010001111000010… |
… | …0010001010110101001010 |
3 | 1120221220110020120102021020 |
4 | 2300203300202022311022 |
5 | 3042241412410224002 |
6 | 41445500041253310 |
7 | 2361403424000502 |
oct | 260436042126512 |
9 | 46856406512236 |
10 | 12133023133002 |
11 | 395864a284562 |
12 | 143b564a94236 |
13 | 6a01a69b80c5 |
14 | 2dd354792a02 |
15 | 16091b3972bc |
hex | b08f088ad4a |
12133023133002 has 48 divisors (see below), whose sum is σ = 24545096702112. Its totient is φ = 3998355672960.
The previous prime is 12133023132983. The next prime is 12133023133003. The reversal of 12133023133002 is 20033132033121.
It is a super-4 number, since 4×121330231330024 (a number of 53 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (12133023133003) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 503620977 + ... + 503645067.
It is an arithmetic number, because the mean of its divisors is an integer number (511356181294).
Almost surely, 212133023133002 is an apocalyptic number.
12133023133002 is an abundant number, since it is smaller than the sum of its proper divisors (12412073569110).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12133023133002 is a wasteful number, since it uses less digits than its factorization.
12133023133002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34871 (or 34782 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 12133023133002 its reverse (20033132033121), we get a palindrome (32166155166123).
The spelling of 12133023133002 in words is "twelve trillion, one hundred thirty-three billion, twenty-three million, one hundred thirty-three thousand, two".
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