Base | Representation |
---|---|
bin | 10001101001111111000… |
… | …011010001110011010011 |
3 | 11021222202211020012211111 |
4 | 101221333003101303103 |
5 | 124334330424441001 |
6 | 2325215450154151 |
7 | 153442003516261 |
oct | 21517703216323 |
9 | 4258684205744 |
10 | 1213312343251 |
11 | 428621206668 |
12 | 177193a22957 |
13 | 8a5515b97a8 |
14 | 42a2055b431 |
15 | 21863788851 |
hex | 11a7f0d1cd3 |
1213312343251 has 2 divisors, whose sum is σ = 1213312343252. Its totient is φ = 1213312343250.
The previous prime is 1213312343153. The next prime is 1213312343267. The reversal of 1213312343251 is 1523432133121.
It is a strong prime.
It is an emirp because it is prime and its reverse (1523432133121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213312343251 - 225 = 1213278788819 is a prime.
It is not a weakly prime, because it can be changed into another prime (1213312343051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606656171625 + 606656171626.
It is an arithmetic number, because the mean of its divisors is an integer number (606656171626).
Almost surely, 21213312343251 is an apocalyptic number.
1213312343251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213312343251 is an equidigital number, since it uses as much as digits as its factorization.
1213312343251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12960, while the sum is 31.
Adding to 1213312343251 its reverse (1523432133121), we get a palindrome (2736744476372).
The spelling of 1213312343251 in words is "one trillion, two hundred thirteen billion, three hundred twelve million, three hundred forty-three thousand, two hundred fifty-one".
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