Base | Representation |
---|---|
bin | 10110100110011000… |
… | …01101111100011011 |
3 | 1011022120121212101121 |
4 | 23103030031330123 |
5 | 144322040130021 |
6 | 5323543030111 |
7 | 606445621612 |
oct | 132314157433 |
9 | 34276555347 |
10 | 12133130011 |
11 | 5166921182 |
12 | 242743b337 |
13 | 11b4907b92 |
14 | 831594879 |
15 | 4b02bb741 |
hex | 2d330df1b |
12133130011 has 2 divisors, whose sum is σ = 12133130012. Its totient is φ = 12133130010.
The previous prime is 12133129999. The next prime is 12133130017. The reversal of 12133130011 is 11003133121.
It is a strong prime.
It is an emirp because it is prime and its reverse (11003133121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12133130011 - 25 = 12133129979 is a prime.
It is not a weakly prime, because it can be changed into another prime (12133130017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066565005 + 6066565006.
It is an arithmetic number, because the mean of its divisors is an integer number (6066565006).
Almost surely, 212133130011 is an apocalyptic number.
12133130011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133130011 is an equidigital number, since it uses as much as digits as its factorization.
12133130011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 12133130011 its reverse (11003133121), we get a palindrome (23136263132).
The spelling of 12133130011 in words is "twelve billion, one hundred thirty-three million, one hundred thirty thousand, eleven".
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