12133212311013 has 4 divisors (see below), whose sum is σ = 16177616414688. Its totient is φ = 8088808207340.

The previous prime is 12133212310981. The next prime is 12133212311021. The reversal of 12133212311013 is 31011321233121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12133212311013 - 2⁵ = 12133212310981 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12133212311713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2022202051833 + ... + 2022202051838.

It is an arithmetic number, because the mean of its divisors is an integer number (4044404103672).

Almost surely, 2^{12133212311013} is an apocalyptic number.

It is an amenable number.

12133212311013 is a deficient number, since it is larger than the sum of its proper divisors (4044404103675).

12133212311013 is an equidigital number, since it uses as much as digits as its factorization.

12133212311013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4044404103674.

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 12133212311013 its reverse (31011321233121), we get a palindrome (43144533544134).

The spelling of 12133212311013 in words is "twelve trillion, one hundred thirty-three billion, two hundred twelve million, three hundred eleven thousand, thirteen".