Base | Representation |
---|---|
bin | 1011000010001111110100… |
… | …0000001111110000100001 |
3 | 1120221220222211020102221022 |
4 | 2300203331000033300201 |
5 | 3042242324440002342 |
6 | 41445532513335225 |
7 | 2361411544160414 |
oct | 260437500176041 |
9 | 46856884212838 |
10 | 12133232344097 |
11 | 3958747388997 |
12 | 143b602b67515 |
13 | 6a020b148b57 |
14 | 2dd374491b7b |
15 | 16092e9209d2 |
hex | b08fd00fc21 |
12133232344097 has 2 divisors, whose sum is σ = 12133232344098. Its totient is φ = 12133232344096.
The previous prime is 12133232344073. The next prime is 12133232344139. The reversal of 12133232344097 is 79044323233121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12132654374416 + 577969681 = 3483196^2 + 24041^2 .
It is a cyclic number.
It is not a de Polignac number, because 12133232344097 - 210 = 12133232343073 is a prime.
It is not a weakly prime, because it can be changed into another prime (12133232344027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066616172048 + 6066616172049.
It is an arithmetic number, because the mean of its divisors is an integer number (6066616172049).
Almost surely, 212133232344097 is an apocalyptic number.
It is an amenable number.
12133232344097 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133232344097 is an equidigital number, since it uses as much as digits as its factorization.
12133232344097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 44.
The spelling of 12133232344097 in words is "twelve trillion, one hundred thirty-three billion, two hundred thirty-two million, three hundred forty-four thousand, ninety-seven".
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