121333144033 has 4 divisors (see below), whose sum is σ = 121968396288. Its totient is φ = 120697891780.

The previous prime is 121333144027. The next prime is 121333144081. The reversal of 121333144033 is 330441333121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121333144033 - 2¹⁷ = 121333012961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121333143992 and 121333144010.

It is not an unprimeable number, because it can be changed into a prime (121333144003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317625841 + ... + 317626222.

It is an arithmetic number, because the mean of its divisors is an integer number (30492099072).

Almost surely, 2^121333144033 is an apocalyptic number.

It is an amenable number.

121333144033 is a deficient number, since it is larger than the sum of its proper divisors (635252255).

121333144033 is an equidigital number, since it uses as much as digits as its factorization.

121333144033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 635252254.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 121333144033 its reverse (330441333121), we get a palindrome (451774477154).

The spelling of 121333144033 in words is "one hundred twenty-one billion, three hundred thirty-three million, one hundred forty-four thousand, thirty-three".