Search a number
-
+
121333144034 = 260666572017
BaseRepresentation
bin111000100000000000…
…1001101100111100010
3102121011220201100022102
41301000001031213202
53441442241102114
6131423434210402
711523514464464
oct1610001154742
9377156640272
10121333144034
114750343aa53
121b622283a02
13b5984583ab
145c30414134
1532520412de
hex1c4004d9e2

121333144034 has 4 divisors (see below), whose sum is σ = 181999716054. Its totient is φ = 60666572016.

The previous prime is 121333144027. The next prime is 121333144081. The reversal of 121333144034 is 430441333121.

It is a happy number.

121333144034 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 99354192025 + 21978952009 = 315205^2 + 148253^2 .

It is a junction number, because it is equal to n+sod(n) for n = 121333143988 and 121333144006.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30333286007 + ... + 30333286010.

Almost surely, 2121333144034 is an apocalyptic number.

121333144034 is a deficient number, since it is larger than the sum of its proper divisors (60666572020).

121333144034 is an equidigital number, since it uses as much as digits as its factorization.

121333144034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60666572019.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 121333144034 its reverse (430441333121), we get a palindrome (551774477155).

The spelling of 121333144034 in words is "one hundred twenty-one billion, three hundred thirty-three million, one hundred forty-four thousand, thirty-four".

Divisors: 1 2 60666572017 121333144034