Base | Representation |
---|---|
bin | 111000100000000000… |
… | …1001101101000010001 |
3 | 102121011220201100101011 |
4 | 1301000001031220101 |
5 | 3441442241102311 |
6 | 131423434210521 |
7 | 11523514464562 |
oct | 1610001155021 |
9 | 377156640334 |
10 | 121333144081 |
11 | 4750343aa96 |
12 | 1b622283a41 |
13 | b598458416 |
14 | 5c30414169 |
15 | 3252041321 |
hex | 1c4004da11 |
121333144081 has 2 divisors, whose sum is σ = 121333144082. Its totient is φ = 121333144080.
The previous prime is 121333144027. The next prime is 121333144087. The reversal of 121333144081 is 180441333121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113067425025 + 8265719056 = 336255^2 + 90916^2 .
It is a cyclic number.
It is not a de Polignac number, because 121333144081 - 221 = 121331046929 is a prime.
It is a super-2 number, since 2×1213331440812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121333144087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60666572040 + 60666572041.
It is an arithmetic number, because the mean of its divisors is an integer number (60666572041).
Almost surely, 2121333144081 is an apocalyptic number.
It is an amenable number.
121333144081 is a deficient number, since it is larger than the sum of its proper divisors (1).
121333144081 is an equidigital number, since it uses as much as digits as its factorization.
121333144081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 121333144081 in words is "one hundred twenty-one billion, three hundred thirty-three million, one hundred forty-four thousand, eighty-one".
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