Base | Representation |
---|---|
bin | 10001101010000000010… |
… | …010100100111011111001 |
3 | 11021222211021100100021011 |
4 | 101222000102210323321 |
5 | 124334401240143001 |
6 | 2325221511513521 |
7 | 153442345306045 |
oct | 21520022447371 |
9 | 4258737310234 |
10 | 1213333131001 |
11 | 428631a14822 |
12 | 17719a9888a1 |
13 | 8a5559b7634 |
14 | 42a2320d025 |
15 | 218654e2d51 |
hex | 11a804a4ef9 |
1213333131001 has 2 divisors, whose sum is σ = 1213333131002. Its totient is φ = 1213333131000.
The previous prime is 1213333130909. The next prime is 1213333131061. The reversal of 1213333131001 is 1001313333121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1104895299600 + 108437831401 = 1051140^2 + 329299^2 .
It is an emirp because it is prime and its reverse (1001313333121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1213333131001 - 215 = 1213333098233 is a prime.
It is not a weakly prime, because it can be changed into another prime (1213333131061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606666565500 + 606666565501.
It is an arithmetic number, because the mean of its divisors is an integer number (606666565501).
Almost surely, 21213333131001 is an apocalyptic number.
It is an amenable number.
1213333131001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1213333131001 is an equidigital number, since it uses as much as digits as its factorization.
1213333131001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 1213333131001 its reverse (1001313333121), we get a palindrome (2214646464122).
The spelling of 1213333131001 in words is "one trillion, two hundred thirteen billion, three hundred thirty-three million, one hundred thirty-one thousand, one".
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