Base | Representation |
---|---|
bin | 1011000010010000001011… |
… | …1001110110110000110011 |
3 | 1120221221020201111120000101 |
4 | 2300210002321312300303 |
5 | 3042243030310112042 |
6 | 41445550411133231 |
7 | 2361414155436334 |
oct | 260440271666063 |
9 | 46857221446011 |
10 | 12133331332147 |
11 | 39587982490a3 |
12 | 143b630144217 |
13 | 6a02257c6b6c |
14 | 2dd38369c28b |
15 | 1609384756b7 |
hex | b0902e76c33 |
12133331332147 has 2 divisors, whose sum is σ = 12133331332148. Its totient is φ = 12133331332146.
The previous prime is 12133331332121. The next prime is 12133331332151. The reversal of 12133331332147 is 74123313333121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12133331332147 is a prime.
It is not a weakly prime, because it can be changed into another prime (12133331332247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066665666073 + 6066665666074.
It is an arithmetic number, because the mean of its divisors is an integer number (6066665666074).
Almost surely, 212133331332147 is an apocalyptic number.
12133331332147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133331332147 is an equidigital number, since it uses as much as digits as its factorization.
12133331332147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 81648, while the sum is 37.
Adding to 12133331332147 its reverse (74123313333121), we get a palindrome (86256644665268).
The spelling of 12133331332147 in words is "twelve trillion, one hundred thirty-three billion, three hundred thirty-one million, three hundred thirty-two thousand, one hundred forty-seven".
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