Base | Representation |
---|---|
bin | 1011000010010000001101… |
… | …0011100000011101111110 |
3 | 1120221221021012011012012020 |
4 | 2300210003103200131332 |
5 | 3042243034020302244 |
6 | 41445551211221010 |
7 | 2361414266544150 |
oct | 260440323403576 |
9 | 46857235135166 |
10 | 12133338056574 |
11 | 39587a1021279 |
12 | 143b632447766 |
13 | 6a022700c807 |
14 | 2dd38452cad0 |
15 | 160938d52d19 |
hex | b09034e077e |
12133338056574 has 16 divisors (see below), whose sum is σ = 27733344129408. Its totient is φ = 3466668016152.
The previous prime is 12133338056563. The next prime is 12133338056617. The reversal of 12133338056574 is 47565083333121.
It is a super-3 number, since 3×121333380565743 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 144444500632 + ... + 144444500715.
It is an arithmetic number, because the mean of its divisors is an integer number (1733334008088).
Almost surely, 212133338056574 is an apocalyptic number.
12133338056574 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
12133338056574 is an abundant number, since it is smaller than the sum of its proper divisors (15600006072834).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12133338056574 is a wasteful number, since it uses less digits than its factorization.
12133338056574 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288889001359.
The product of its (nonzero) digits is 5443200, while the sum is 51.
The spelling of 12133338056574 in words is "twelve trillion, one hundred thirty-three billion, three hundred thirty-eight million, fifty-six thousand, five hundred seventy-four".
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