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1213352533121 = 47731376134211
BaseRepresentation
bin10001101010000001011…
…100100101110010000001
311021222212121212001222012
4101222001130211302001
5124334421222024441
62325223443422305
7153443002235021
oct21520134456201
94258777761865
101213352533121
11428641966933
121771a5384995
138a559a1b891
1442a25a1da81
15218670769eb
hex11a81725c81

1213352533121 has 32 divisors (see below), whose sum is σ = 1267677485568. Its totient is φ = 1160547056640.

The previous prime is 1213352533111. The next prime is 1213352533147.

1213352533121 is nontrivially palindromic in base 10.

It is a cyclic number.

It is not a de Polignac number, because 1213352533121 - 210 = 1213352532097 is a prime.

It is a super-2 number, since 2×12133525331212 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1213352533111) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 288136706 + ... + 288140916.

It is an arithmetic number, because the mean of its divisors is an integer number (39614921424).

Almost surely, 21213352533121 is an apocalyptic number.

It is an amenable number.

1213352533121 is a deficient number, since it is larger than the sum of its proper divisors (54324952447).

1213352533121 is a wasteful number, since it uses less digits than its factorization.

1213352533121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5081.

The product of its digits is 16200, while the sum is 32.

The spelling of 1213352533121 in words is "one trillion, two hundred thirteen billion, three hundred fifty-two million, five hundred thirty-three thousand, one hundred twenty-one".

Divisors: 1 47 73 137 613 3431 4211 6439 10001 28811 44749 83981 197917 307403 470047 576907 2103203 2581343 3947107 6130613 14447941 27114629 42114211 121323121 188438039 288138811 353643991 1979367917 8856587833 16621267577 25816011343 1213352533121