Base | Representation |
---|---|
bin | 10001101010000001011… |
… | …100100101110010000001 |
3 | 11021222212121212001222012 |
4 | 101222001130211302001 |
5 | 124334421222024441 |
6 | 2325223443422305 |
7 | 153443002235021 |
oct | 21520134456201 |
9 | 4258777761865 |
10 | 1213352533121 |
11 | 428641966933 |
12 | 1771a5384995 |
13 | 8a559a1b891 |
14 | 42a25a1da81 |
15 | 218670769eb |
hex | 11a81725c81 |
1213352533121 has 32 divisors (see below), whose sum is σ = 1267677485568. Its totient is φ = 1160547056640.
The previous prime is 1213352533111. The next prime is 1213352533147.
1213352533121 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 1213352533121 - 210 = 1213352532097 is a prime.
It is a super-2 number, since 2×12133525331212 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1213352533111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 288136706 + ... + 288140916.
It is an arithmetic number, because the mean of its divisors is an integer number (39614921424).
Almost surely, 21213352533121 is an apocalyptic number.
It is an amenable number.
1213352533121 is a deficient number, since it is larger than the sum of its proper divisors (54324952447).
1213352533121 is a wasteful number, since it uses less digits than its factorization.
1213352533121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5081.
The product of its digits is 16200, while the sum is 32.
The spelling of 1213352533121 in words is "one trillion, two hundred thirteen billion, three hundred fifty-two million, five hundred thirty-three thousand, one hundred twenty-one".
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