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12134050211055 = 354730091710193
BaseRepresentation
bin1011000010010010110111…
…0000001010010011101111
31120222000002211012101111010
42300210231300022103233
53042301013323223210
641450150011200303
72361441035010243
oct260445560122357
946860084171433
1012134050211055
1139590270124a3
12143b7b0a46093
136a030b7162b6
142dd410d4c423
1516097b626920
hexb092dc0a4ef

12134050211055 has 16 divisors (see below), whose sum is σ = 19414532734560. Its totient is φ = 6471475980288.

The previous prime is 12134050211039. The next prime is 12134050211083. The reversal of 12134050211055 is 55011205043121.

It is not a de Polignac number, because 12134050211055 - 24 = 12134050211039 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6240039 + ... + 7950231.

It is an arithmetic number, because the mean of its divisors is an integer number (1213408295910).

Almost surely, 212134050211055 is an apocalyptic number.

12134050211055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12134050211055 is a deficient number, since it is larger than the sum of its proper divisors (7280482523505).

12134050211055 is a wasteful number, since it uses less digits than its factorization.

12134050211055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2183210.

The product of its (nonzero) digits is 6000, while the sum is 30.

Adding to 12134050211055 its reverse (55011205043121), we get a palindrome (67145255254176).

The spelling of 12134050211055 in words is "twelve trillion, one hundred thirty-four billion, fifty million, two hundred eleven thousand, fifty-five".

Divisors: 1 3 5 15 473009 1419027 1710193 2365045 5130579 7095135 8550965 25652895 808936680737 2426810042211 4044683403685 12134050211055