Base | Representation |
---|---|
bin | 1011000010010010110111… |
… | …0000001010010011101111 |
3 | 1120222000002211012101111010 |
4 | 2300210231300022103233 |
5 | 3042301013323223210 |
6 | 41450150011200303 |
7 | 2361441035010243 |
oct | 260445560122357 |
9 | 46860084171433 |
10 | 12134050211055 |
11 | 39590270124a3 |
12 | 143b7b0a46093 |
13 | 6a030b7162b6 |
14 | 2dd410d4c423 |
15 | 16097b626920 |
hex | b092dc0a4ef |
12134050211055 has 16 divisors (see below), whose sum is σ = 19414532734560. Its totient is φ = 6471475980288.
The previous prime is 12134050211039. The next prime is 12134050211083. The reversal of 12134050211055 is 55011205043121.
It is not a de Polignac number, because 12134050211055 - 24 = 12134050211039 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6240039 + ... + 7950231.
It is an arithmetic number, because the mean of its divisors is an integer number (1213408295910).
Almost surely, 212134050211055 is an apocalyptic number.
12134050211055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12134050211055 is a deficient number, since it is larger than the sum of its proper divisors (7280482523505).
12134050211055 is a wasteful number, since it uses less digits than its factorization.
12134050211055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2183210.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 12134050211055 its reverse (55011205043121), we get a palindrome (67145255254176).
The spelling of 12134050211055 in words is "twelve trillion, one hundred thirty-four billion, fifty million, two hundred eleven thousand, fifty-five".
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