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12134130343 = 101311978411
BaseRepresentation
bin10110100110100000…
…00010001010100111
31011022122111200120221
423103100002022213
5144322314132333
65324020305211
7606460256206
oct132320021247
934278450527
1012134130343
1151674447a5
122427842207
1311b4b982aa
1483177523d
154b0417d2d
hex2d34022a7

12134130343 has 4 divisors (see below), whose sum is σ = 12146109768. Its totient is φ = 12122150920.

The previous prime is 12134130317. The next prime is 12134130361. The reversal of 12134130343 is 34303143121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34303143121 = 132638703317.

It is a cyclic number.

It is not a de Polignac number, because 12134130343 - 213 = 12134122151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12134130643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5988193 + ... + 5990218.

It is an arithmetic number, because the mean of its divisors is an integer number (3036527442).

Almost surely, 212134130343 is an apocalyptic number.

12134130343 is a deficient number, since it is larger than the sum of its proper divisors (11979425).

12134130343 is a wasteful number, since it uses less digits than its factorization.

12134130343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11979424.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12134130343 its reverse (34303143121), we get a palindrome (46437273464).

The spelling of 12134130343 in words is "twelve billion, one hundred thirty-four million, one hundred thirty thousand, three hundred forty-three".

Divisors: 1 1013 11978411 12134130343