Base | Representation |
---|---|
bin | 1011000010010011110101… |
… | …1100010001010000100001 |
3 | 1120222000210011111101212121 |
4 | 2300210331130101100201 |
5 | 3042302033214311342 |
6 | 41450232053024241 |
7 | 2361450412235443 |
oct | 260447534212041 |
9 | 46860704441777 |
10 | 12134313432097 |
11 | 395915165634a |
12 | 143b865025081 |
13 | 6a03511076ac |
14 | 2dd437caa493 |
15 | 1609947bd067 |
hex | b093d711421 |
12134313432097 has 2 divisors, whose sum is σ = 12134313432098. Its totient is φ = 12134313432096.
The previous prime is 12134313432091. The next prime is 12134313432127. The reversal of 12134313432097 is 79023431343121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12014708818176 + 119604613921 = 3466224^2 + 345839^2 .
It is an emirp because it is prime and its reverse (79023431343121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12134313432097 - 211 = 12134313430049 is a prime.
It is not a weakly prime, because it can be changed into another prime (12134313432091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067156716048 + 6067156716049.
It is an arithmetic number, because the mean of its divisors is an integer number (6067156716049).
Almost surely, 212134313432097 is an apocalyptic number.
It is an amenable number.
12134313432097 is a deficient number, since it is larger than the sum of its proper divisors (1).
12134313432097 is an equidigital number, since it uses as much as digits as its factorization.
12134313432097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 43.
The spelling of 12134313432097 in words is "twelve trillion, one hundred thirty-four billion, three hundred thirteen million, four hundred thirty-two thousand, ninety-seven".
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