Base | Representation |
---|---|
bin | 1011000010010011111000… |
… | …0001001010101001100001 |
3 | 1120222000210211200210201022 |
4 | 2300210332001022221201 |
5 | 3042302043203314403 |
6 | 41450233040215225 |
7 | 2361450560401442 |
oct | 260447601125141 |
9 | 46860724623638 |
10 | 12134323104353 |
11 | 395915706224a |
12 | 143b86830a515 |
13 | 6a0353113018 |
14 | 2dd4392a72c9 |
15 | 16099557dd38 |
hex | b093e04aa61 |
12134323104353 has 2 divisors, whose sum is σ = 12134323104354. Its totient is φ = 12134323104352.
The previous prime is 12134323104313. The next prime is 12134323104373. The reversal of 12134323104353 is 35340132343121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10681967915584 + 1452355188769 = 3268328^2 + 1205137^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12134323104353 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (12134323104313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067161552176 + 6067161552177.
It is an arithmetic number, because the mean of its divisors is an integer number (6067161552177).
Almost surely, 212134323104353 is an apocalyptic number.
It is an amenable number.
12134323104353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12134323104353 is an equidigital number, since it uses as much as digits as its factorization.
12134323104353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 35.
Adding to 12134323104353 its reverse (35340132343121), we get a palindrome (47474455447474).
The spelling of 12134323104353 in words is "twelve trillion, one hundred thirty-four billion, three hundred twenty-three million, one hundred four thousand, three hundred fifty-three".
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