Base | Representation |
---|---|
bin | 111000100000010101… |
… | …1000011000111000001 |
3 | 102121012200100112012212 |
4 | 1301000223003013001 |
5 | 3442003043023131 |
6 | 131424505231505 |
7 | 11524006632326 |
oct | 1610053030701 |
9 | 377180315185 |
10 | 121344111041 |
11 | 4750965069a |
12 | 1b625a92595 |
13 | b59a7c814a |
14 | 5c31a6ab4d |
15 | 3252eaaa2b |
hex | 1c40ac31c1 |
121344111041 has 2 divisors, whose sum is σ = 121344111042. Its totient is φ = 121344111040.
The previous prime is 121344111001. The next prime is 121344111061. The reversal of 121344111041 is 140111443121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109823308816 + 11520802225 = 331396^2 + 107335^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121344111041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121344110998 and 121344111016.
It is not a weakly prime, because it can be changed into another prime (121344111001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60672055520 + 60672055521.
It is an arithmetic number, because the mean of its divisors is an integer number (60672055521).
Almost surely, 2121344111041 is an apocalyptic number.
It is an amenable number.
121344111041 is a deficient number, since it is larger than the sum of its proper divisors (1).
121344111041 is an equidigital number, since it uses as much as digits as its factorization.
121344111041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 121344111041 its reverse (140111443121), we get a palindrome (261455554162).
The spelling of 121344111041 in words is "one hundred twenty-one billion, three hundred forty-four million, one hundred eleven thousand, forty-one".
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