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121344111041 is a prime number
BaseRepresentation
bin111000100000010101…
…1000011000111000001
3102121012200100112012212
41301000223003013001
53442003043023131
6131424505231505
711524006632326
oct1610053030701
9377180315185
10121344111041
114750965069a
121b625a92595
13b59a7c814a
145c31a6ab4d
153252eaaa2b
hex1c40ac31c1

121344111041 has 2 divisors, whose sum is σ = 121344111042. Its totient is φ = 121344111040.

The previous prime is 121344111001. The next prime is 121344111061. The reversal of 121344111041 is 140111443121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109823308816 + 11520802225 = 331396^2 + 107335^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121344111041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121344110998 and 121344111016.

It is not a weakly prime, because it can be changed into another prime (121344111001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60672055520 + 60672055521.

It is an arithmetic number, because the mean of its divisors is an integer number (60672055521).

Almost surely, 2121344111041 is an apocalyptic number.

It is an amenable number.

121344111041 is a deficient number, since it is larger than the sum of its proper divisors (1).

121344111041 is an equidigital number, since it uses as much as digits as its factorization.

121344111041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 121344111041 its reverse (140111443121), we get a palindrome (261455554162).

The spelling of 121344111041 in words is "one hundred twenty-one billion, three hundred forty-four million, one hundred eleven thousand, forty-one".