Base | Representation |
---|---|
bin | 10001101010000110110… |
… | …010101001011011110111 |
3 | 11022000002212120200122011 |
4 | 101222012302221123313 |
5 | 124340112200420320 |
6 | 2325240405345051 |
7 | 153445141346260 |
oct | 21520662513367 |
9 | 4260085520564 |
10 | 1213442201335 |
11 | 4286885409a1 |
12 | 17720b408187 |
13 | 8a5724857b0 |
14 | 42a338c1967 |
15 | 2186ed8a05a |
hex | 11a86ca96f7 |
1213442201335 has 32 divisors (see below), whose sum is σ = 1814846423040. Its totient is φ = 758346496128.
The previous prime is 1213442201333. The next prime is 1213442201353. The reversal of 1213442201335 is 5331022443121.
It is not a de Polignac number, because 1213442201335 - 21 = 1213442201333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1213442201297 and 1213442201306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213442201333) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16843207 + ... + 16915096.
It is an arithmetic number, because the mean of its divisors is an integer number (56713950720).
Almost surely, 21213442201335 is an apocalyptic number.
1213442201335 is a deficient number, since it is larger than the sum of its proper divisors (601404221705).
1213442201335 is a wasteful number, since it uses less digits than its factorization.
1213442201335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33758407.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1213442201335 its reverse (5331022443121), we get a palindrome (6544464644456).
The spelling of 1213442201335 in words is "one trillion, two hundred thirteen billion, four hundred forty-two million, two hundred one thousand, three hundred thirty-five".
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