1213450211341 has 4 divisors (see below), whose sum is σ = 1239268300992. Its totient is φ = 1187632121692.

The previous prime is 1213450211327. The next prime is 1213450211357. The reversal of 1213450211341 is 1431120543121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1213450211341 - 2³³ = 1204860276749 is a prime.

It is a super-2 number, since 2×1213450211341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213450511341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12909044755 + ... + 12909044848.

It is an arithmetic number, because the mean of its divisors is an integer number (309817075248).

Almost surely, 2^{1213450211341} is an apocalyptic number.

It is an amenable number.

1213450211341 is a deficient number, since it is larger than the sum of its proper divisors (25818089651).

1213450211341 is an equidigital number, since it uses as much as digits as its factorization.

1213450211341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25818089650.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 1213450211341 its reverse (1431120543121), we get a palindrome (2644570754462).

The spelling of 1213450211341 in words is "one trillion, two hundred thirteen billion, four hundred fifty million, two hundred eleven thousand, three hundred forty-one".