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12135113 is a prime number
BaseRepresentation
bin101110010010…
…101011001001
3211211112020122
4232102223021
511101310423
61112033025
7205101224
oct56225311
924745218
1012135113
116939321
124092775
13268b653
14187c5bb
1510ea8c8
hexb92ac9

12135113 has 2 divisors, whose sum is σ = 12135114. Its totient is φ = 12135112.

The previous prime is 12135103. The next prime is 12135121. The reversal of 12135113 is 31153121.

12135113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9048064 + 3087049 = 3008^2 + 1757^2 .

It is a cyclic number.

It is not a de Polignac number, because 12135113 - 212 = 12131017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12135091 and 12135100.

It is not a weakly prime, because it can be changed into another prime (12135103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6067556 + 6067557.

It is an arithmetic number, because the mean of its divisors is an integer number (6067557).

Almost surely, 212135113 is an apocalyptic number.

It is an amenable number.

12135113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12135113 is an equidigital number, since it uses as much as digits as its factorization.

12135113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 90, while the sum is 17.

The square root of 12135113 is about 3483.5489087998. The cubic root of 12135113 is about 229.7988979403.

Adding to 12135113 its reverse (31153121), we get a palindrome (43288234).

The spelling of 12135113 in words is "twelve million, one hundred thirty-five thousand, one hundred thirteen".