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121351343434 = 288211687847
BaseRepresentation
bin111000100000100011…
…0101000110101001010
3102121020011221222012021
41301001012220311022
53442011420442214
6131425324235054
711524125254116
oct1610106506512
9377204858167
10121351343434
1147512740482
121b62839ba8a
13b59c15b079
145c329d0746
153253938924
hex1c411a8d4a

121351343434 has 8 divisors (see below), whose sum is σ = 182029343328. Its totient is φ = 60674895660.

The previous prime is 121351343411. The next prime is 121351343437. The reversal of 121351343434 is 434343153121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1213513434342 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 121351343434.

It is not an unprimeable number, because it can be changed into a prime (121351343437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167502 + ... + 520345.

It is an arithmetic number, because the mean of its divisors is an integer number (22753667916).

Almost surely, 2121351343434 is an apocalyptic number.

121351343434 is a deficient number, since it is larger than the sum of its proper divisors (60677999894).

121351343434 is an equidigital number, since it uses as much as digits as its factorization.

121351343434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 776060.

The product of its digits is 51840, while the sum is 34.

Adding to 121351343434 its reverse (434343153121), we get a palindrome (555694496555).

The spelling of 121351343434 in words is "one hundred twenty-one billion, three hundred fifty-one million, three hundred forty-three thousand, four hundred thirty-four".

Divisors: 1 2 88211 176422 687847 1375694 60675671717 121351343434