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121353231451321 is a prime number
BaseRepresentation
bin11011100101111011000000…
…010000001100010010111001
3120220200020220100111101122201
4123211323000100030102321
5111401222404222420241
61110032523243150201
734363324126553302
oct3345730020142271
9526606810441581
10121353231451321
1135737686533681
121173b09b815361
1352937398c50ac
1421d775619d7a9
15e06a21982931
hex6e5ec040c4b9

121353231451321 has 2 divisors, whose sum is σ = 121353231451322. Its totient is φ = 121353231451320.

The previous prime is 121353231451297. The next prime is 121353231451337. The reversal of 121353231451321 is 123154132353121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75544970938921 + 45808260512400 = 8691661^2 + 6768180^2 .

It is a cyclic number.

It is not a de Polignac number, because 121353231451321 - 217 = 121353231320249 is a prime.

It is not a weakly prime, because it can be changed into another prime (121353231401321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60676615725660 + 60676615725661.

It is an arithmetic number, because the mean of its divisors is an integer number (60676615725661).

Almost surely, 2121353231451321 is an apocalyptic number.

It is an amenable number.

121353231451321 is a deficient number, since it is larger than the sum of its proper divisors (1).

121353231451321 is an equidigital number, since it uses as much as digits as its factorization.

121353231451321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64800, while the sum is 37.

The spelling of 121353231451321 in words is "one hundred twenty-one trillion, three hundred fifty-three billion, two hundred thirty-one million, four hundred fifty-one thousand, three hundred twenty-one".