Base | Representation |
---|---|
bin | 1011000010011111110001… |
… | …1010011111100010010111 |
3 | 1120222100001110100120112102 |
4 | 2300213330122133202113 |
5 | 3042330113424231201 |
6 | 41451522025312315 |
7 | 2361622665523244 |
oct | 260477432374227 |
9 | 46870043316472 |
10 | 12137517414551 |
11 | 395a546179831 |
12 | 14403ba03569b |
13 | 6a0741b3bab9 |
14 | 2dd65d6105cb |
15 | 160ad0c0626b |
hex | b09fc69f897 |
12137517414551 has 16 divisors (see below), whose sum is σ = 13088451398400. Its totient is φ = 11217816561600.
The previous prime is 12137517414479. The next prime is 12137517414577. The reversal of 12137517414551 is 15541471573121.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12137517414551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12137517414496 and 12137517414505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12137517434551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21122636 + ... + 21689646.
It is an arithmetic number, because the mean of its divisors is an integer number (818028212400).
Almost surely, 212137517414551 is an apocalyptic number.
12137517414551 is a deficient number, since it is larger than the sum of its proper divisors (950933983849).
12137517414551 is a wasteful number, since it uses less digits than its factorization.
12137517414551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 594550.
The product of its digits is 588000, while the sum is 47.
Adding to 12137517414551 its reverse (15541471573121), we get a palindrome (27678988987672).
The spelling of 12137517414551 in words is "twelve trillion, one hundred thirty-seven billion, five hundred seventeen million, four hundred fourteen thousand, five hundred fifty-one".
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