1214014312303 has 4 divisors (see below), whose sum is σ = 1307400028648. Its totient is φ = 1120628595960.

The previous prime is 1214014312289. The next prime is 1214014312307. The reversal of 1214014312303 is 3032134104121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214014312303 - 2⁵ = 1214014312271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214014312307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46692858153 + ... + 46692858178.

It is an arithmetic number, because the mean of its divisors is an integer number (326850007162).

Almost surely, 2^{1214014312303} is an apocalyptic number.

1214014312303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1214014312303 is a deficient number, since it is larger than the sum of its proper divisors (93385716345).

1214014312303 is an equidigital number, since it uses as much as digits as its factorization.

1214014312303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93385716344.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1214014312303 its reverse (3032134104121), we get a palindrome (4246148416424).

The spelling of 1214014312303 in words is "one trillion, two hundred fourteen billion, fourteen million, three hundred twelve thousand, three hundred three".