Base | Representation |
---|---|
bin | 1011000010101001110100… |
… | …1110100111011110111111 |
3 | 1120222121000111011010021020 |
4 | 2300222131032213132333 |
5 | 3042401130122330101 |
6 | 41453045445235223 |
7 | 2362046566354551 |
oct | 260523516473677 |
9 | 46877014133236 |
10 | 12140215433151 |
11 | 3960700132073 |
12 | 1440a31702b13 |
13 | 6a0a81ab0700 |
14 | 2dd837a894d1 |
15 | 160bdc9e9136 |
hex | b0a9d3a77bf |
12140215433151 has 24 divisors (see below), whose sum is σ = 17536770323856. Its totient is φ = 7467114620160.
The previous prime is 12140215433147. The next prime is 12140215433231. The reversal of 12140215433151 is 15133451204121.
It is not a de Polignac number, because 12140215433151 - 22 = 12140215433147 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12140215433351) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5067910 + ... + 7068531.
It is an arithmetic number, because the mean of its divisors is an integer number (730698763494).
Almost surely, 212140215433151 is an apocalyptic number.
12140215433151 is a deficient number, since it is larger than the sum of its proper divisors (5396554890705).
12140215433151 is a wasteful number, since it uses less digits than its factorization.
12140215433151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12138443 (or 12138430 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 12140215433151 its reverse (15133451204121), we get a palindrome (27273666637272).
The spelling of 12140215433151 in words is "twelve trillion, one hundred forty billion, two hundred fifteen million, four hundred thirty-three thousand, one hundred fifty-one".
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