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12140215433151 = 3132197312136441
BaseRepresentation
bin1011000010101001110100…
…1110100111011110111111
31120222121000111011010021020
42300222131032213132333
53042401130122330101
641453045445235223
72362046566354551
oct260523516473677
946877014133236
1012140215433151
113960700132073
121440a31702b13
136a0a81ab0700
142dd837a894d1
15160bdc9e9136
hexb0a9d3a77bf

12140215433151 has 24 divisors (see below), whose sum is σ = 17536770323856. Its totient is φ = 7467114620160.

The previous prime is 12140215433147. The next prime is 12140215433231. The reversal of 12140215433151 is 15133451204121.

It is not a de Polignac number, because 12140215433151 - 22 = 12140215433147 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12140215433351) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5067910 + ... + 7068531.

It is an arithmetic number, because the mean of its divisors is an integer number (730698763494).

Almost surely, 212140215433151 is an apocalyptic number.

12140215433151 is a deficient number, since it is larger than the sum of its proper divisors (5396554890705).

12140215433151 is a wasteful number, since it uses less digits than its factorization.

12140215433151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12138443 (or 12138430 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 12140215433151 its reverse (15133451204121), we get a palindrome (27273666637272).

The spelling of 12140215433151 in words is "twelve trillion, one hundred forty billion, two hundred fifteen million, four hundred thirty-three thousand, one hundred fifty-one".

Divisors: 1 3 13 39 169 507 1973 5919 25649 76947 333437 1000311 12136441 36409323 157773733 473321199 2051058529 6153175587 23945198093 71835594279 311287575209 933862725627 4046738477717 12140215433151