Base | Representation |
---|---|
bin | 10001101010101001111… |
… | …001001011000100100111 |
3 | 11022001121220201120200011 |
4 | 101222221321023010213 |
5 | 124342313431131120 |
6 | 2325415044031051 |
7 | 153465552131341 |
oct | 21525171130447 |
9 | 4261556646604 |
10 | 1214031114535 |
11 | 42895aa07118 |
12 | 177354692487 |
13 | 8a63749bc45 |
14 | 42a8bbc0291 |
15 | 218a6917c5a |
hex | 11aa9e4b127 |
1214031114535 has 8 divisors (see below), whose sum is σ = 1463199073920. Its totient is φ = 966983733984.
The previous prime is 1214031114511. The next prime is 1214031114553. The reversal of 1214031114535 is 5354111304121.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1214031114535 - 27 = 1214031114407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1214031114497 and 1214031114506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 530143447 + ... + 530145736.
It is an arithmetic number, because the mean of its divisors is an integer number (182899884240).
Almost surely, 21214031114535 is an apocalyptic number.
1214031114535 is a deficient number, since it is larger than the sum of its proper divisors (249167959385).
1214031114535 is a wasteful number, since it uses less digits than its factorization.
1214031114535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1060289417.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 1214031114535 its reverse (5354111304121), we get a palindrome (6568142418656).
The spelling of 1214031114535 in words is "one trillion, two hundred fourteen billion, thirty-one million, one hundred fourteen thousand, five hundred thirty-five".
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