Base | Representation |
---|---|
bin | 10001101010101010000… |
… | …110101011110110010001 |
3 | 11022001122011101112112212 |
4 | 101222222012223312101 |
5 | 124342320333003112 |
6 | 2325415252001505 |
7 | 153465624213254 |
oct | 21525206536621 |
9 | 4261564345485 |
10 | 1214034656657 |
11 | 428961a06399 |
12 | 177355900295 |
13 | 8a63813c284 |
14 | 42a8c46309b |
15 | 218a6db7522 |
hex | 11aaa1abd91 |
1214034656657 has 2 divisors, whose sum is σ = 1214034656658. Its totient is φ = 1214034656656.
The previous prime is 1214034656651. The next prime is 1214034656699. The reversal of 1214034656657 is 7566564304121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 948751973521 + 265282683136 = 974039^2 + 515056^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1214034656657 is a prime.
It is not a weakly prime, because it can be changed into another prime (1214034656651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607017328328 + 607017328329.
It is an arithmetic number, because the mean of its divisors is an integer number (607017328329).
Almost surely, 21214034656657 is an apocalyptic number.
It is an amenable number.
1214034656657 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214034656657 is an equidigital number, since it uses as much as digits as its factorization.
1214034656657 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 50.
The spelling of 1214034656657 in words is "one trillion, two hundred fourteen billion, thirty-four million, six hundred fifty-six thousand, six hundred fifty-seven".
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