Base | Representation |
---|---|
bin | 10001101010101010011… |
… | …111011101011101100111 |
3 | 11022001122121121111120111 |
4 | 101222222133131131213 |
5 | 124342324013320320 |
6 | 2325420043113451 |
7 | 153466033343215 |
oct | 21525237353547 |
9 | 4261577544514 |
10 | 1214041151335 |
11 | 4289656419a1 |
12 | 177357b12887 |
13 | 8a6395a448c |
14 | 42a8d273cb5 |
15 | 218a774ba5a |
hex | 11aaa7dd767 |
1214041151335 has 16 divisors (see below), whose sum is σ = 1506406551552. Its totient is φ = 938301559200.
The previous prime is 1214041151293. The next prime is 1214041151347. The reversal of 1214041151335 is 5331511404121.
It is a happy number.
It is not a de Polignac number, because 1214041151335 - 215 = 1214041118567 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1214041151297 and 1214041151306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6580671 + ... + 6762640.
It is an arithmetic number, because the mean of its divisors is an integer number (94150409472).
Almost surely, 21214041151335 is an apocalyptic number.
1214041151335 is a deficient number, since it is larger than the sum of its proper divisors (292365400217).
1214041151335 is a wasteful number, since it uses less digits than its factorization.
1214041151335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13343934.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 1214041151335 its reverse (5331511404121), we get a palindrome (6545552555456).
The spelling of 1214041151335 in words is "one trillion, two hundred fourteen billion, forty-one million, one hundred fifty-one thousand, three hundred thirty-five".
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