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12141041477 = 19639002183
BaseRepresentation
bin10110100111010100…
…11001011101000101
31011100010111210212212
423103222121131011
5144331101311402
65324424353205
7606603102245
oct132352313505
934303453785
1012141041477
115170335184
12242a015805
1311b6447c16
14832653b25
154b0d30952
hex2d3a99745

12141041477 has 4 divisors (see below), whose sum is σ = 12780043680. Its totient is φ = 11502039276.

The previous prime is 12141041459. The next prime is 12141041537. The reversal of 12141041477 is 77414014121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12141041477 - 226 = 12073932613 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12141041447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 319501073 + ... + 319501110.

It is an arithmetic number, because the mean of its divisors is an integer number (3195010920).

Almost surely, 212141041477 is an apocalyptic number.

It is an amenable number.

12141041477 is a deficient number, since it is larger than the sum of its proper divisors (639002203).

12141041477 is an equidigital number, since it uses as much as digits as its factorization.

12141041477 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 639002202.

The product of its (nonzero) digits is 6272, while the sum is 32.

Adding to 12141041477 its reverse (77414014121), we get a palindrome (89555055598).

The spelling of 12141041477 in words is "twelve billion, one hundred forty-one million, forty-one thousand, four hundred seventy-seven".

Divisors: 1 19 639002183 12141041477