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12141135543401 is a prime number
BaseRepresentation
bin1011000010101101010000…
…0100100011110001101001
31120222200101121111120020122
42300223110010203301221
53042410021144342101
641453321034333025
72362111441231664
oct260532404436151
946880347446218
1012141135543401
11396103254a567
12144104988a175
136a0b9a5c8747
142dd8c3d5c6db
15160c4369951b
hexb0ad4123c69

12141135543401 has 2 divisors, whose sum is σ = 12141135543402. Its totient is φ = 12141135543400.

The previous prime is 12141135543379. The next prime is 12141135543431. The reversal of 12141135543401 is 10434553114121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7580771022400 + 4560364521001 = 2753320^2 + 2135501^2 .

It is a cyclic number.

It is not a de Polignac number, because 12141135543401 - 242 = 7743089032297 is a prime.

It is not a weakly prime, because it can be changed into another prime (12141135543431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070567771700 + 6070567771701.

It is an arithmetic number, because the mean of its divisors is an integer number (6070567771701).

Almost surely, 212141135543401 is an apocalyptic number.

It is an amenable number.

12141135543401 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141135543401 is an equidigital number, since it uses as much as digits as its factorization.

12141135543401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 12141135543401 its reverse (10434553114121), we get a palindrome (22575688657522).

The spelling of 12141135543401 in words is "twelve trillion, one hundred forty-one billion, one hundred thirty-five million, five hundred forty-three thousand, four hundred one".