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12141222101401 is a prime number
BaseRepresentation
bin1011000010101101100100…
…1110110000000110011001
31120222200121122101011111111
42300223121032300012121
53042410210324221101
641453333405500321
72362113542040451
oct260533116600631
946880548334444
1012141222101401
11396107739a8a8
1214410728716a1
136a0bb2513ab3
142dd8d1650d61
15160c4b096251
hexb0ad93b0199

12141222101401 has 2 divisors, whose sum is σ = 12141222101402. Its totient is φ = 12141222101400.

The previous prime is 12141222101329. The next prime is 12141222101413. The reversal of 12141222101401 is 10410122214121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10710722380176 + 1430499721225 = 3272724^2 + 1196035^2 .

It is a cyclic number.

It is not a de Polignac number, because 12141222101401 - 217 = 12141221970329 is a prime.

It is a super-3 number, since 3×121412221014013 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12141222101441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070611050700 + 6070611050701.

It is an arithmetic number, because the mean of its divisors is an integer number (6070611050701).

Almost surely, 212141222101401 is an apocalyptic number.

It is an amenable number.

12141222101401 is a deficient number, since it is larger than the sum of its proper divisors (1).

12141222101401 is an equidigital number, since it uses as much as digits as its factorization.

12141222101401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 22.

Adding to 12141222101401 its reverse (10410122214121), we get a palindrome (22551344315522).

The spelling of 12141222101401 in words is "twelve trillion, one hundred forty-one billion, two hundred twenty-two million, one hundred one thousand, four hundred one".