121412341404443 has 4 divisors (see below), whose sum is σ = 122614443794688. Its totient is φ = 120210239014200.

The previous prime is 121412341404383. The next prime is 121412341404463. The reversal of 121412341404443 is 344404143214121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121412341404443 - 2²⁸ = 121412072968987 is a prime.

It is a super-4 number, since 4×121412341404443⁴ (a number of 57 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121412341404397 and 121412341404406.

It is not an unprimeable number, because it can be changed into a prime (121412341404463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601051194971 + ... + 601051195172.

It is an arithmetic number, because the mean of its divisors is an integer number (30653610948672).

Almost surely, 2^{121412341404443} is an apocalyptic number.

121412341404443 is a deficient number, since it is larger than the sum of its proper divisors (1202102390245).

121412341404443 is a wasteful number, since it uses less digits than its factorization.

121412341404443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1202102390244.

The product of its (nonzero) digits is 147456, while the sum is 38.

Adding to 121412341404443 its reverse (344404143214121), we get a palindrome (465816484618564).

The spelling of 121412341404443 in words is "one hundred twenty-one trillion, four hundred twelve billion, three hundred forty-one million, four hundred four thousand, four hundred forty-three".