Base | Representation |
---|---|
bin | 11011100110110010000011… |
… | …011110110001001100101111 |
3 | 120220212220110211022010122111 |
4 | 123212302003132301030233 |
5 | 111403204433344420323 |
6 | 1110120020514424451 |
7 | 34400516001065224 |
oct | 3346620336611457 |
9 | 526786424263574 |
10 | 121412341404463 |
11 | 3575a75956731a |
12 | 1174a637592127 |
13 | 5299199b32025 |
14 | 21da56276794b |
15 | e08330ec2c0d |
hex | 6e6c837b132f |
121412341404463 has 2 divisors, whose sum is σ = 121412341404464. Its totient is φ = 121412341404462.
The previous prime is 121412341404383. The next prime is 121412341404481. The reversal of 121412341404463 is 364404143214121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121412341404463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121419341404463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60706170702231 + 60706170702232.
It is an arithmetic number, because the mean of its divisors is an integer number (60706170702232).
Almost surely, 2121412341404463 is an apocalyptic number.
121412341404463 is a deficient number, since it is larger than the sum of its proper divisors (1).
121412341404463 is an equidigital number, since it uses as much as digits as its factorization.
121412341404463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 221184, while the sum is 40.
Adding to 121412341404463 its reverse (364404143214121), we get a palindrome (485816484618584).
The spelling of 121412341404463 in words is "one hundred twenty-one trillion, four hundred twelve billion, three hundred forty-one million, four hundred four thousand, four hundred sixty-three".
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