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121413103142 = 260706551571
BaseRepresentation
bin111000100010011001…
…0001110111000100110
3102121101111011200120212
41301010302032320212
53442123223300032
6131435412055422
711525505230432
oct1610462167046
9377344150525
10121413103142
1147544593461
121b645004572
13b5abba2c86
145c3aca99c2
153259087bb2
hex1c44c8ee26

121413103142 has 4 divisors (see below), whose sum is σ = 182119654716. Its totient is φ = 60706551570.

The previous prime is 121413103129. The next prime is 121413103169. The reversal of 121413103142 is 241301314121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241301314121 = 734471616303.

It is a super-2 number, since 2×1214131031422 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30353275784 + ... + 30353275787.

It is an arithmetic number, because the mean of its divisors is an integer number (45529913679).

Almost surely, 2121413103142 is an apocalyptic number.

121413103142 is a deficient number, since it is larger than the sum of its proper divisors (60706551574).

121413103142 is an equidigital number, since it uses as much as digits as its factorization.

121413103142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60706551573.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 121413103142 its reverse (241301314121), we get a palindrome (362714417263).

The spelling of 121413103142 in words is "one hundred twenty-one billion, four hundred thirteen million, one hundred three thousand, one hundred forty-two".

Divisors: 1 2 60706551571 121413103142