Base | Representation |
---|---|
bin | 10110100111011101… |
… | …00011101101000011 |
3 | 1011100012120012211220 |
4 | 23103232203231003 |
5 | 144331341211120 |
6 | 5324504010123 |
7 | 606615263565 |
oct | 132356435503 |
9 | 34305505756 |
10 | 12142132035 |
11 | 5170a0a570 |
12 | 242a460943 |
13 | 11b673a417 |
14 | 832859335 |
15 | 4b0e98b40 |
hex | 2d3ba3b43 |
12142132035 has 32 divisors (see below), whose sum is σ = 21200078592. Its totient is φ = 5885278080.
The previous prime is 12142132033. The next prime is 12142132081. The reversal of 12142132035 is 53023124121.
It is not a de Polignac number, because 12142132035 - 21 = 12142132033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12142131996 and 12142132014.
It is not an unprimeable number, because it can be changed into a prime (12142132033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 636912 + ... + 655698.
It is an arithmetic number, because the mean of its divisors is an integer number (662502456).
Almost surely, 212142132035 is an apocalyptic number.
12142132035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12142132035 is a deficient number, since it is larger than the sum of its proper divisors (9057946557).
12142132035 is a wasteful number, since it uses less digits than its factorization.
12142132035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22723.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 12142132035 its reverse (53023124121), we get a palindrome (65165256156).
The spelling of 12142132035 in words is "twelve billion, one hundred forty-two million, one hundred thirty-two thousand, thirty-five".
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