Base | Representation |
---|---|
bin | 10110100111011110… |
… | …01101111101111111 |
3 | 1011100012220000022121 |
4 | 23103233031331333 |
5 | 144331412231101 |
6 | 5324511423411 |
7 | 606616614364 |
oct | 132357157577 |
9 | 34305800277 |
10 | 12142305151 |
11 | 5171018639 |
12 | 242a524b67 |
13 | 11b679b162 |
14 | 8328a246b |
15 | 4b0ed00a1 |
hex | 2d3bcdf7f |
12142305151 has 4 divisors (see below), whose sum is σ = 12143595600. Its totient is φ = 12141014704.
The previous prime is 12142305101. The next prime is 12142305173. The reversal of 12142305151 is 15150324121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12142305151 - 27 = 12142305023 is a prime.
It is a super-2 number, since 2×121423051512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12142305101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 631006 + ... + 649963.
It is an arithmetic number, because the mean of its divisors is an integer number (3035898900).
Almost surely, 212142305151 is an apocalyptic number.
12142305151 is a deficient number, since it is larger than the sum of its proper divisors (1290449).
12142305151 is an equidigital number, since it uses as much as digits as its factorization.
12142305151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1290448.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 12142305151 its reverse (15150324121), we get a palindrome (27292629272).
The spelling of 12142305151 in words is "twelve billion, one hundred forty-two million, three hundred five thousand, one hundred fifty-one".
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