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12143010433 is a prime number
BaseRepresentation
bin10110100111100011…
…11010001010000001
31011100021012211210011
423103301322022001
5144332102313213
65324534504521
7606625612531
oct132361721201
934307184704
1012143010433
11517145a514
12242a805141
1311b6987198
14832a074c1
154b10be03d
hex2d3c7a281

12143010433 has 2 divisors, whose sum is σ = 12143010434. Its totient is φ = 12143010432.

The previous prime is 12143010419. The next prime is 12143010437. The reversal of 12143010433 is 33401034121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7660975729 + 4482034704 = 87527^2 + 66948^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143010433 - 213 = 12143002241 is a prime.

It is not a weakly prime, because it can be changed into another prime (12143010437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071505216 + 6071505217.

It is an arithmetic number, because the mean of its divisors is an integer number (6071505217).

Almost surely, 212143010433 is an apocalyptic number.

It is an amenable number.

12143010433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143010433 is an equidigital number, since it uses as much as digits as its factorization.

12143010433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 12143010433 its reverse (33401034121), we get a palindrome (45544044554).

The spelling of 12143010433 in words is "twelve billion, one hundred forty-three million, ten thousand, four hundred thirty-three".