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12143044013100 = 223527111340436377
BaseRepresentation
bin1011000010110100010111…
…0100110010110000101100
31120222212022121121212111120
42300231011310302300230
53042422423231404400
641454234251420540
72362206644035410
oct260550564626054
946885277555446
1012143044013100
113961921860050
1214414a0a54750
136a1112b06460
142dda255ccd40
15160d05ecbca0
hexb0b45d32c2c

12143044013100 has 288 divisors, whose sum is σ = 47172755083776. Its totient is φ = 2329135257600.

The previous prime is 12143044013083. The next prime is 12143044013123. The reversal of 12143044013100 is 131044034121.

It is a super-2 number, since 2×121430440131002 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 19917889 + ... + 20518488.

Almost surely, 212143044013100 is an apocalyptic number.

12143044013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12143044013100 is an abundant number, since it is smaller than the sum of its proper divisors (35029711070676).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12143044013100 is a wasteful number, since it uses less digits than its factorization.

12143044013100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40436425 (or 40436418 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 12143044013100 its reverse (131044034121), we get a palindrome (12274088047221).

The spelling of 12143044013100 in words is "twelve trillion, one hundred forty-three billion, forty-four million, thirteen thousand, one hundred".