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121431221447 = 389312162523
BaseRepresentation
bin111000100010111011…
…1010110010011000111
3102121102202021012020012
41301011313112103013
53442142343041242
6131441300300435
711526115231454
oct1610567262307
9377382235205
10121431221447
1147553838a68
121b64b0a171b
13b5b2877a73
145c3d46482b
15325a966282
hex1c45dd64c7

121431221447 has 4 divisors (see below), whose sum is σ = 121743384360. Its totient is φ = 121119058536.

The previous prime is 121431221393. The next prime is 121431221449. The reversal of 121431221447 is 744122134121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121431221447 - 212 = 121431217351 is a prime.

It is a super-2 number, since 2×1214312214472 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121431221449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156080873 + ... + 156081650.

It is an arithmetic number, because the mean of its divisors is an integer number (30435846090).

Almost surely, 2121431221447 is an apocalyptic number.

121431221447 is a deficient number, since it is larger than the sum of its proper divisors (312162913).

121431221447 is an equidigital number, since it uses as much as digits as its factorization.

121431221447 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 312162912.

The product of its digits is 10752, while the sum is 32.

Adding to 121431221447 its reverse (744122134121), we get a palindrome (865553355568).

The spelling of 121431221447 in words is "one hundred twenty-one billion, four hundred thirty-one million, two hundred twenty-one thousand, four hundred forty-seven".

Divisors: 1 389 312162523 121431221447