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12143200431 = 34047733477
BaseRepresentation
bin10110100111100101…
…01000100010101111
31011100021120111102010
423103302220202233
5144332124403211
65324542532303
7606630333465
oct132362504257
934307514363
1012143200431
11517157a23a
12242a897093
1311b6a227cb
14832a56835
154b110a4a6
hex2d3ca88af

12143200431 has 4 divisors (see below), whose sum is σ = 16190933912. Its totient is φ = 8095466952.

The previous prime is 12143200427. The next prime is 12143200457. The reversal of 12143200431 is 13400234121.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12143200431 - 22 = 12143200427 is a prime.

It is a super-2 number, since 2×121432004312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12143200398 and 12143200407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12143200471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2023866736 + ... + 2023866741.

It is an arithmetic number, because the mean of its divisors is an integer number (4047733478).

Almost surely, 212143200431 is an apocalyptic number.

12143200431 is a deficient number, since it is larger than the sum of its proper divisors (4047733481).

12143200431 is an equidigital number, since it uses as much as digits as its factorization.

12143200431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4047733480.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 12143200431 its reverse (13400234121), we get a palindrome (25543434552).

The spelling of 12143200431 in words is "twelve billion, one hundred forty-three million, two hundred thousand, four hundred thirty-one".

Divisors: 1 3 4047733477 12143200431