Base | Representation |
---|---|
bin | 10110100111100101… |
… | …01000100011010111 |
3 | 1011100021120111110121 |
4 | 23103302220203113 |
5 | 144332124403341 |
6 | 5324542532411 |
7 | 606630333553 |
oct | 132362504327 |
9 | 34307514417 |
10 | 12143200471 |
11 | 517157a276 |
12 | 242a897107 |
13 | 11b6a2282c |
14 | 832a56863 |
15 | 4b110a4d1 |
hex | 2d3ca88d7 |
12143200471 has 2 divisors, whose sum is σ = 12143200472. Its totient is φ = 12143200470.
The previous prime is 12143200469. The next prime is 12143200477. The reversal of 12143200471 is 17400234121.
It is a weak prime.
It is an emirp because it is prime and its reverse (17400234121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12143200471 - 21 = 12143200469 is a prime.
It is a super-3 number, since 3×121432004713 (a number of 31 digits) contains 333 as substring.
Together with 12143200469, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12143200477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071600235 + 6071600236.
It is an arithmetic number, because the mean of its divisors is an integer number (6071600236).
Almost surely, 212143200471 is an apocalyptic number.
12143200471 is a deficient number, since it is larger than the sum of its proper divisors (1).
12143200471 is an equidigital number, since it uses as much as digits as its factorization.
12143200471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 12143200471 its reverse (17400234121), we get a palindrome (29543434592).
The spelling of 12143200471 in words is "twelve billion, one hundred forty-three million, two hundred thousand, four hundred seventy-one".
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